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56x^2=-11x+15
We move all terms to the left:
56x^2-(-11x+15)=0
We get rid of parentheses
56x^2+11x-15=0
a = 56; b = 11; c = -15;
Δ = b2-4ac
Δ = 112-4·56·(-15)
Δ = 3481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3481}=59$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-59}{2*56}=\frac{-70}{112} =-5/8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+59}{2*56}=\frac{48}{112} =3/7 $
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